$I=\sqrt{\frac{\dot{Q}}{R}}$
Alternatively, the rate of heat transfer from the wire can also be calculated by:
A 2-m-diameter and 4-m-long horizontal cylinder is maintained at a uniform temperature of 80°C. Water flows across the cylinder at 15°C with a velocity of 3.5 m/s. Determine the rate of heat transfer.
$\dot{Q}=62.5 \times \pi \times 0.004 \times 2 \times (80-20)=100.53W$
$\dot{Q}=\frac{T_{s}-T_{\infty}}{\frac{1}{2\pi kL}ln(\frac{r_{o}+t}{r_{o}})}$
$\dot{Q}_{rad}=1 \times 5.67 \times 10^{-8} \times 1.5 \times (305^{4}-293^{4})=41.9W$